在 2020/2/5 下午5:52, Jonathan Wakely 写道:
>
> I think that's correct. The attribute grammar is confusing, but it
> does apply to the return type as used above, and that's obviously
> meaningless since 'int' has no calling convention.
>
But this error only occurs when declaring a pointer-to-member-function
using the `typedef` declaration, not a using-declaration:
```c++
class Z;
int main() {
extern int __attribute__((__stdcall__)) A(void);
__attribute__((__stdcall__)) extern int A(void);
extern int A(void) __attribute__((__stdcall__)); // ok
typedef int __attribute__((__stdcall__)) (*B)(void);
typedef __attribute__((__stdcall__)) int (*B)(void);
typedef int (*B)(void) __attribute__((__stdcall__)); // ok
typedef int __attribute__((__fastcall__)) (*C)(void);
typedef __attribute__((__fastcall__)) int (*C)(void);
typedef int (*C)(void) __attribute__((__fastcall__)); // ok
typedef int __attribute__((__stdcall__)) (Z::*D)(void);
typedef __attribute__((__stdcall__)) int (Z::*D)(void);
typedef int (Z::*D)(void) __attribute__((__stdcall__)); // ok
typedef int __attribute__((__fastcall__)) (Z::*E)(void);
typedef __attribute__((__fastcall__)) int (Z::*E)(void);
typedef int (Z::*E)(void) __attribute__((__fastcall__)); // error
}
```
```
lh_mouse@lhmouse-ideapad ~/Desktop $ i686-w64-mingw32-g++ test.c
test.c: In function ‘int main()’:
test.c:20:57: error: fastcall and stdcall attributes are not compatible
typedef int __attribute__((__fastcall__)) (Z::*E)(void);
^
test.c:21:57: error: fastcall and stdcall attributes are not compatible
typedef __attribute__((__fastcall__)) int (Z::*E)(void);
^
test.c:22:57: error: fastcall and stdcall attributes are not compatible
typedef int (Z::*E)(void) __attribute__((__fastcall__));
^
```
--
Best regards,
LH_Mouse
