On Thu, 6 Jun 2019 at 02:35, esoteric escape <manips88@xxxxxxxxx> wrote: > > Thanks! It was a little tricky to take in especially when code pages are involved. > > So, > > If -finput-charset and -fexec-charset are the same then no conversion is performed. That is clear. > If -finput-charset and -fexec-charset are not set then no conversion is performed either. Because it appears, GCC cannot get system locale under Windows so -finput-charset is UTF-8 by default and so is -fexec-charset so again both are same. Right. > Only if only of these are specified, then a conversion is performed and -fexec-charset is always UTF-8. -fexec-charset is UTF-8 by default, but you can change it. > That means if I use Windows 1251 or a UTF-8 source file, Using Windows 1251 or UTF-8 source files is irrelevant. GCC doesn't know what you think the source file contains. All that matters is the values of the options and any codeset specified by the locale. > with none of these options specified, then only raw bytes will be read and no conversion will happen at all? If you don't use -finput-charset or -fexec-charset (and you're on Windows so there's no locale codeset) then the two charsets are the same, so no conversion happens.
