Hello, I am on Windows OS where CHAR_BIT == 8. I am trying to understand whether this behavior is implementation-defined or not. I have this string in UTF-8, and I am trying to understand if it is implementation-defined: std::string s = u8"€"; It's clear to me that char c = 0xC8 is implementation defined for the reasons: 1. char's signedness depends on compiler.. 2. If the value is beyond the representatable range of char say, -128 to 127, then again it is implementation-defined. In the same way, I am trying to understand how the std::string case is handled because its also uses char. So, € in UTF-8 means E2 82 AC sequence of bytes in hex. If std::string uses suppose signed version of char, don't they fall beyond the representable range and therefore, their value is implementation defined in std::string? Or, is this case actually well-defined?
