On 9 April 2018 at 22:46, Bostjan Mihoric wrote:
> typedef struct MyItemType { double d; } MyItemType;
>
> double Fun1(MyItemType mit)
> {
> return mit.d;
> }
>
> int main(int argc, char* argv[])
> {
> // This is ok. Works as expected. If I wanted initializer
> // to represent a different type, I would cast it.
> MyItemType mit1 = { 1.0 };
> MyItemType mit2 = { .d = 1.0 };
>
> // These require a cast.
> mit1 = (MyItemType){ 1.0 };
> mit2 = (MyItemType){ .d = 1.0 };
> Fun1((MyItemType){ 1.0 });
> Fun1((MyItemType){ .d = 1.0 });
> }
>
>
> Is there a way of doing initializers in second group without doing a cast?
Only in C++. The C standard defines a compound literal as (type-name){
initializer-list }. If you don't have the type-name then it's not a
compound literal.
