On Tue, Feb 6, 2018 at 7:27 PM, Jonathan Wakely <jwakely.gcc@xxxxxxxxx> wrote: > On 6 February 2018 at 18:23, Peter T. Breuer <ptb@xxxxxxxxxxxxxx> wrote: >> "Also sprach Jonathan Wakely:" >>> >> The specification of each operator tells you if it's applied. 6.5.7 >>> >> doesn't say they are, so they aren't. >> >> (attempt to apply no say = must not ignored for the purposes of a >> communicative interaction with the humanZ here ...) >> >>> > I don't have a "specification of each operator" to look at ... probably >>> > it doesn't junp out from google for me as easily as other stuff does. >>> >>> See the C standard. >> >> Where specifically? I am now looking at the draft standard for >> ISO-whatever at >> >> http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf > > The specification of each operator of course! > > You've been pointed to them multiple times now, 6.5.5, and 6.5.6, and > 6.5.7, and so on. > > Are you trolling or just stubborn and unable to accept the help you asked for? > > Maybe this will help: > http://en.cppreference.com/w/c/language/conversion#Usual_arithmetic_conversions > And specifically: > http://en.cppreference.com/w/c/language/operator_arithmetic#Shift_operators > > But feel free to shift the goalposts again and insist that somebody > proves the correctness of those pages, or some other way to move the > burden of proof from your mistaken interpretation to everybody else. @Peter Breuer: it seems that you are not very knowledgeable about the internals of the C language. Hence, I would like to invite you to study this very good resource on the internals of the C language: http://publications.gbdirect.co.uk/c_book/. -- Best regards, Tadeus
