I'm having trouble using Power8's vcipher instruction. I want to use '__vcipher' because it takes and returns an unsigned char array. Also see https://www.ibm.com/support/knowledgecenter/en/SSGH3R_13.1.3/com.ibm.xlcpp1313.aix.doc/compiler_ref/bif_crypto_aes_vcipher.html. So far I've only been able to use __builtin_crypto_vcipher, and that requires casts to/from 64-bit types. For example, the following does not compile: typedef vector unsigned char uint8x16_p8; typedef vector unsigned long uint64x2_p8; uint8x16_p8 block = (uint8x16_p8)vec_vsx_ld(0, inBlock); block = __builtin_crypto_vcipher(block, (uint8x16_p8)vec_ld( 16, (const byte*)subkeys)); block = __builtin_crypto_vcipher(block, (uint8x16_p8)vec_ld( 32, (const byte*)subkeys)); ... it results in: rijndael-test.cpp:23:95: error: cannot convert 'uint8x16_p8 {aka __vector(16) unsigned char}' to '__vector(2) long unsigned int' for argument '1' to '__vector(2) long unsigned int __builtin_crypto_vcipher(__vector(2) long unsigned int, __vector(2) long unsigned int)' If I cast to a 64-bit type to get past the compile errors, then I cannot arrive at the correct result. (I may not arrive at the correct result with the 8-bit type, but that's what I am trying to discover). I found a couple of mailing lists posts that talk about Power8 endian swaps when using types other than 8-bit. That's why I want to avoid the 64-bit type. Also see https://gcc.gnu.org/ml/gcc/2015-03/msg00143.html. How can I use Power8 vcipher with 8-bit types? Jeff
