reinterpret_cast is not a constant expression - needed help to find solution

[Zygmunt Ptak <zygmuntptak@xxxxxxxxx>]

Hi,

I have a code for AVR written in c++.
To get the same size result as C code I'm using template classes.
For example:

#define AVR_REG_TO_U16(REG) (reinterpret_cast<u16>(& REG))

template<typename RegType, u16 reg_r>
struct Register
{
    typedef Register<RegType, reg_r> Type;
    constexpr Register<RegType, reg_r>() {}
    static RegType & reg() { return *reinterpret_cast<RegType*>(reg_r); }
    void operator = (RegType value) { reg() = value; }
    void setBit(RegType value)   { reg() = static_cast<RegType>(reg()
| 1 << value); }
    void dropBit(RegType value)  { reg() = static_cast<RegType>(reg()
& ~(1 << value)); }
    void clear()                 { reg() = 0; }
    void setBits(RegType mask)   { reg() = static_cast<RegType>(reg()
|  mask); }
    void clearBits(RegType mask) { reg() = static_cast<RegType>(reg()
& ~mask); }
    operator RegType() { return reg(); }
} __attribute__((packed));

// and finally:

Register<volatile uint8_t, AVR_REG_TO_U16(PIND)> pin_d;
pin_d.setBit(1);

Everything works pretty cool on old compiler.
But on newer (in my case gcc-7.1.0) there is an error:

error: 'reinterpret_cast<volatile uint8_t* {aka volatile unsigned
char*}>(41)' is not a constant expression

I tried found some solution, but nothing.
All the time the same problem.
Is it possible to turn off that option?

I understand that this type of the code doesn't make a sens on PC, but
on AVR it really does.

Of course that simple example looks like not having any benefit.
But it has, compiler nicely optimize code and as I said I'm able to
get the same size of the code like in pure C.
Size is really matter here with 2kB of the SRAM on atmega328p.
I don't want to use pure C. I want to use C++ which is better for my project.

Best regards
Zygmunt Ptak