> No, that is not how it works. 6.2.4/2 says: [...] "The value of a > pointer becomes indeterminate when the object it points to (or just > past) reaches the end of its lifetime." > > It does not matter whether the value of p changes in *your* system, > or in most systems. Using the value of p after deallocating the object > it pointed to is undefined behaviour. > Does this mean that the following fragment is invalid? (I think it isn't.) void *p, *q; p = malloc(123); q = p; free(p); if (p == q) ... Thanks. Andrew Makhorin
