On Sun, Feb 19, 2017 at 04:44:43PM +0100, Chris Pezley wrote:
> int main( void )
> {
> int32_t high_part;
> int32_t low_part;
> int64_t together;
>
> const int64_t id = 0xAAAAAAAAAAAA;
>
> high_part = id >> 32;
> low_part = id & 0xFFFFFFFF;
> together = (int64_t)high_part << 32 | low_part;
The way you write it, low_part is implicitly cast to int64_t. It is
signed and negative, so it gets 1 bits in the top half.
Segher
