Why GCC prefers global size-unaware deallocation function?

[Ruslan Garipov <brigadir15@xxxxxxxxx>]

I have the following `operator delete` replacements:

void operator delete[](void* p)
{
  /* Implementation does not matter. */
}

void operator delete[](void* p, std::size_t size)
{
  /* Implementation does not matter. */
}

My question is why, in the following code, GCC 6.2 calls `void
operator delete[](void*)` and not the second replacement:

char* str = new char[14];
delete[] str;


According to 5.3.5 Delete [expr.delete]:

> (10.3) If the type is complete and if, for the second alternative (delete array) only, the operand is a pointer to a class type with a non-trivial destructor or a (possibly multi-dimensional) array thereof, the function with a parameter of type std::size_t is selected.

Therefore, I believe `operator delete[](void*, std::size_t)` must be
called, doesn't it?

Thanks.