----- Original Message ----- > On 12/11/2016 08:04, nick wrote: > > > On 2016-11-12 01:37 AM, Andrew Pinski wrote: > > > >> Anyways I think the problem is you assume > >> new Record*[N]; will NULL out the array. It does not. PMJI. If you want value initialization then you need to write new Record*[N](); otherwise you get default initialization which for a builtin type like a pointer means not initialized. A+ Paul
