On 29/10/2015, staticx wrote: > I wonder if I can pass the content of a bash variable as an argument to > gcc. > My variable is a list of optimization options like $var="-opt1 -opt2 -opt3" > gcc $var test.c -o object.o didn't work Because that's not how you set shell variables. It should be var="..." not $var="..." This has nothing to do with GCC, you're just using the shell wrong.
