conversions betwwen function pointers and their calls

[Dima Sorkin <dima.sorkin@xxxxxxxxx>]

Hi,

1. I have read that the C99 standard allows conversions between
   function pointer types (6.3.2.3 paragraph 8). But if I don't want
   such conversions to appear mistakingly in program - is there any
   command line option to issue a warning?

2. Consider the example below, it was compiled by
   GCC 4.9.1 20140903 (prerelease) with
   'gcc -std=c99 -pedantic -Wall -Wextra'. I don't understand
   why the compiler allows calling of function pointer 'g' of
   type 'void (*)()' with arguments...

Thanks, regards,
  Dima.

----- EXAMPLE: -----

#include<stdio.h>

void f(double x) { printf("x=%f\n",x); }

typedef void (*f_with_no_args_type)();
typedef void (*f_type)(double);

int main() {

  // standart allows it (why not still warn?)
  f_with_no_args_type g = f;


  g(3.14);  // <- BUT WHY COMPILER IS SILENT HERE?
  g(1.0,2.0,3); // <- AND HERE
  g();

  f_type h = f;

  h(3.14);
  // h(1.0,2.0,3); // compilation error -- ok
  // h(); // compilation error -- ok

  return 0;
}