On 11 June 2014 16:16, Christoph Mathys wrote: > Now, is this the expected behaviour of shared_ptr? Do I need to check > myself that my smart_ptr is non-nil similar to "manual" bounds > checking when using operator[] on std::vector? Yes, but a much better analogy than std::vector is using a normal pointer. Don't dereference it unless you know it's non-null.
