On 28/08/12 05:58, Anna Sidera wrote: > The system has 10 giga byte RAM. > > The command: > uname -a > gives the following output: > Linux olympus 2.6.26-2-amd64 #1 SMP Wed Aug 19 22:33:18 UTC 2009 x86_64 GNU/Linux > I think this means that the system is 64 bit. It does. > So you think that the command: > int myvariable = 1000; > float *myarray = malloc(pow(myvariable,3)*sizeof(float)); > will work if pow(myvariable,3) is smaller than 2 billion? > > Many Thanks, > Anna Yes. (the 2+e9 limit being roughly for the 7,45GB needed, not due to malloc, to which you could ask for even bigger amounts )
