Found partially answer of my question http://gcc.gnu.org/ml/gcc-help/2006-10/msg00059.html there i.e. derivatives of template class should use this->x instead of x to be able to get member x. The problem is that it seems related not only to x but rather to all members of Der and it precedents i.e. in same example as in link above: template<class T> class Base { protected: T x; Base() {} int DummyBase; }; template <class T> class Der: public Base<T> { public: using Base<T>::x; Der():Base<T>() {} int get(); void DoSmth(); int DummyDer; }; template <class T> void Der<T>::DoSmth() { return DummyBase+DummyDer; // compiler shouts that both DummyDer and DummyBase are out of scope. } So, what's the reason for compiler to do so? What means "two pass compilation of the templates" and why it leads to so unfavorable results? -- View this message in context: http://old.nabble.com/Usage-of-properties-methods-in-derivative-of-template-class-tp34061358p34061358.html Sent from the gcc - Help mailing list archive at Nabble.com.
