"Mathematically, the tangent function has singularities at odd
multiples
of pi/2. If the argument x is too close to one of these singularities, tan will signal overflow."
Since pi is irrational, pi/2 is also irrational and therefore infinitely long when represented in any base. It is impossible to represent pi/2 in any floating point number format. Therefore, it's impossible to pass pi/2 into tan() and impossible to hit a singularity. You might like to feed it values that are very close to see whether you can make the result overflow.
