2011/3/29 José Luis García Pallero: > Hello, > In the function bellow I pass two const pointers to a function. One > pointer to a char** and the other to char*. When I compiling the > program via gcc test.c -o test I obtain a warning: > > test.c:18:5: warning: passing argument 1 of ‘foo’ from incompatible pointer type > test.c:4:6: note: expected ‘const char **’ but argument is of type ‘char **’ > > What is the reason for the warning? I won't change the char** argument > in the function so I think that declare it as const is correct. What > the argument const char* do no emits a warning? I tested the program > with gcc 4.5.2 and 4.6.0 and I obtain the warning in each compiler. See the C++ FAQ Lite (this question applies to both C and C++): http://www.parashift.com/c++-faq-lite/const-correctness.html#faq-18.17
