where is __is_trivial used in type_traits 4.5.1 defined?

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In:

http://gcc.gnu.org/viewcvs/trunk/libstdc%2B%2B-v3/include/std/type_traits?revision=169421&view=markup

on line 625, there's:

: public integral_constant<bool, __is_trivial(_Tp)>

Since _Tp is a type, not a value, I thought
__is_trivial must be a macro; however, grepping
the include directory produced nothing:

find . -type f -exec grep __is_trivial {} \; -ls
    : public integral_constant<bool, __is_trivial(_Tp)>
2966263   20 -rw-r--r--   1 evansl   evansl      17946 Aug 25 02:31
./type_traits

Where is __is_trivial defined so I can look  at it to
try and understand why g++ doesn't complain, when compiling
type_traits, that _Tp is a type and not a value?

TIA.

-regards,
Larry



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