Re: Floating point: just 20 digits of precision

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On Mon, 29 Nov 2010, Vincent Lefevre wrote:

On 2010-11-26 16:10:39 +0100, Marc Glisse wrote:
long double would be binary80.

Not even that. In binary{k}, k is required to be either 16 or a
multiple of 32.

That's the "would" part ;-)

Moreover these interchange formats use the implicit
bit, which is not the case of Intel's double-extended format.

Ah, right, I forgot about that, thanks for the correction.

--
Marc Glisse


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