Axel Freyn wrote:
>
> Hi,
>>
>> david.hagood wrote:
>> >
>> > On Thu, 2010-10-07 at 14:08 -0700, brac37 wrote:
>> >> Hello,
>> >>
>> >> I have some code that works when I make class classA public. But I
>> only
>> >> want
>> >> class classA to be accessible by itself and class classB. So the
>> problem
>> >> is
>> >> very concrete: make classB a friend of classA.
>> >>
>> >> Here is the code that describes both classes.
>> >>
>> >>
>> >>
>> >> template <class T, int C> class classA;
>> >>
>> >> template <class T, int C, classA<T,C> &instanceA> class classB;
>> >>
>> >> template <class T, int C> class classA
>> >> {
>> >>
>> >> template <classA &instanceA> friend class classB;
>> > I think your problem is that you are not fully specifying the template
>> > parameters for class B, thus as far as class A is concerned, you are
>> > speaking of some other class B.
>> >
>> > I think you have to fully spec out class B here:
>> >
>> > friend class classB<T,C,classA&>;
>> >
>>
>> No, that does not work. This time, the error is given already before
>> instantiation. The error is that that the third parameter ClassA & is not
>> of
>> the right kind: it is a type instead of a constant instance of that type.
> This is the same problem as in your other mail: You try to make a
> partial template specialization of classB to be friend of classA. That
> won't work (if I understood the C++-Standard correctly in this point...)
>
> What you can do, is to make friend the "complete" template classA:
> template <class T1, int C1, classA<T1, C1> &instanceA> friend class
> classB;
>
> works.
>
>
> Axel
>
>
There is only a partial specialization syntactically, but not semantically.
However, your method works.
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