Hi,
is returning const references to temporaries/local variables always an
error (assuming the variable is local, not static, and not a member
variable)? Why does g++ only generate warnings, not errors? Because it
is legal C++, but not useful? Or undefined behavior?
struct Base1 {};
struct Derived1 : public Base1 {};
const Base1& f1() { Base1 x; return x; }
const Base1& f2() { return Base1(); }
const Base1& f3() { Derived1 x; return x; }
const Base1& f4() { return Derived1(); }
struct Base2 { int foo; };
struct Derived2 : public Base2 {};
const Base2& f5() { Base2 x; return x; }
const Base2& f6() { return Base2(); }
const Base2& f7() { Derived2 x; return x; }
const Base2& b8() { return Derived2(); }
BTW g++ generates a warning for all cases except the last one. I guess
there should be a warning as well or am I missing something?
Joachim
