Hi, I have a doubt in linker script MEMORY command. I have divided my available memory area into 3 regions as follows: MEMORY { stack(w): org = 0x8000000, len = 0x50000 runtime(w) : org = 0x8050010, len = 0x400000 swimage(wx): org = 0x8450020, len = 0x30000 } The swimage region contains text section as well as copy of .data, .bss(LMA). The runtime region contains .data, .bss sections (VMA). When I use objdump -p command to dump the program header for the .out generated with the above linker script MEMORY split, the lower address is interpreted as 0x8000000. The higher and execution addresses are dumped as expected. However, I would like to get the lower address of memory region as the start address of swimage region i.e 0x8450020. How can I get that? Please suggest. Thanks and regards, Jeffi -- View this message in context: http://old.nabble.com/How-to-split-memory-in-linker-script-to-get-the-lower-address-as-start-of-.text--tp28251238p28251238.html Sent from the gcc - Help mailing list archive at Nabble.com.