I think we're saying the same thing :) It will work for the program when it can see the headers, and implicit instantiation is allowed. On Sat, Mar 6, 2010 at 4:00 AM, John Graham <johngavingraham@xxxxxxxxxxxxxx> wrote: >> I believe that since you are forcing explicit instantiation, >> you will probably have to instantiate ALL used templates, even if they >> are templates used by an instantiated template. Maybe someone in the >> know could confirm? > > Fair enough - no mean feat since the compiler nicely tells you what > it's missing, I guess. It's just a puzzle to me that I didn't seem to > have to do any extra "instantiating" in my library but I do in a test > case - I'm obviously missing something subtle in the library. > > >> Perhaps you aren't using the same flag in the compilation of your >> program, and the code can see the template directly? Then you would >> have the explicitly instantiated subclass, and because you aren't >> telling the compiler to explicitly instantiate while compiling the >> executable, it takes care of implicitly instantiating anything used by >> the subclass? This is just a guess. Do you use that flag for >> compilation of all units? > > In the example I sent earlier (as in the "real" case) I use > -fno-implicit-templates for the library, but *not* for the program. > And the program can definitely see all the template definitions as > they're included in header files, so I don't think that'll be the > case... > > John G >
