Hi Ian,
Thanks, It worked for me, actually there is a small mistake in
HARD_REGNO_MODE_OK function in which it was mistakenly taking register group
i.e. 2 register which was defined for double integer. I corrected that and
it worked as expected.
Thanks,
Prashant.
Ian Lance Taylor-3 wrote:
>
> Prashant Purohit <prashantpurohit025@xxxxxxxxx> writes:
>
>> I have defined REG_ALLOC_ORDER for my dummy target on GCC-4.3.0
>> as
>>
>> #define REG_ALLOC_ORDER \
>> { \
>> 3, 2, 1, 0, 12, 14, 4, 5, \
>> 6, 7, 8, 10, 9, 11, 13, 15, \
>> 16, 17, 18 \
>> }
>>
>> But instead of allocating register r3 first it is allocating
>> register r2 then I tried some different combination and found that it is
>> actually allocating even no. Register first.
>>
>> I want my compiler to use r3 first while allocating register, is
>> there anything extra I need to do or I missed out?
>
> If you find that the compiler is allocating even registers first, then
> almost certainly there is some machine mode or some insn which
> requires an even registers. Do you have a register class which
> contains only the even registers? Are there any modes which are only
> permitted in the even registers (see HARD_REGNO_MODE_OK)?
>
> Ian
>
>
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