On Wed, 20 Jan 2010, Dr. David Kirkby wrote:
On Solaris, where both 32 and 64-bit executables are built, it is necessary
to use the -m64 flag to gcc/g++/gfortran to build 64-bit binaries. On some
code I see people as:
LDFLAGS=-m64
before building the code. My understanding is that LDFLAGS is passed to the
linker. Neither the GNU or Sun linkers have -m64 as an option (the Sun linker
supports -64, but not -m64). So I can't understand how this does not generate
an error message. Not only does if fail to generate an error, but some code
will simply not build without having -m64 in LDFLAGS.
Can anyone explain this to me please?
LDFLAGS is passed to $LD, which nowadays should be gcc (or g++, gfortran).
gcc in turn will call ld with options that ld can understand (it may
actually go through collect2 in between).
--
Marc Glisse
