Re: no Loop Invariant Motion?

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On Sun, 2010-01-03 at 11:24 +0530, prashant rawat wrote:
> I have a simple C code :
> 
> #include<stdio.h>
> int *c;
> int main ()
> {
>         int a=0, b;
>         while (a < 100)
>         {
>                         b = 10;
>                         a = a + 1;
>         }
>         c = &b;
>         printf ("%d\n", *c);
>         return 0;
> }
> 
> I would basically expect the b = 10 statement to be moved out of the
> while loop, as it is an invariant.
> However, it does not seem to happen in the *.lim dump file.
> I am using gcc 4.4.2 to compile, and the cmd line options are
> install/bin/gcc -fdump-tree-all -O3 filename.c
> 
> Can anyone explain what went wrong?
> 

My version of gcc (4.4.1) completely eliminates the loop since it it
irrelevant. Notice that a is not used beyond the loop. gcc generates the
following assembly language:

	.file	"loop_invar.c"
	.section	.rodata.str1.1,"aMS",@progbits,1
.LC0:
	.string	"%d\n"
	.text
	.p2align 4,,15
.globl main
	.type	main, @function
main:
.LFB22:
	.cfi_startproc
	subq	$24, %rsp
	.cfi_def_cfa_offset 32
	movl	$10, %edx      # 3rd argument to printf
	movl	$.LC0, %esi    # address of format string
	leaq	12(%rsp), %rax # address of b
	movl	$1, %edi       # check stack overflow
	movl	$10, 12(%rsp)  # b = 10;
	movq	%rax, c(%rip)  # c = &b;
	xorl	%eax, %eax     # no floats
	call	__printf_chk
	xorl	%eax, %eax     # return 0;
	addq	$24, %rsp
	ret
	.cfi_endproc
.LFE22:
	.size	main, .-main
	.comm	c,8,8
	.ident	"GCC: (Ubuntu 4.4.1-4ubuntu8) 4.4.1"
	.section	.note.GNU-stack,"",@progbits

which is the equivalent of:
#include<stdio.h>
int *c;
int main ()
{
        int b;
        b = 10;
        c = &b;
        printf ("%d\n", 10);
        return 0;
}

--Bob





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