This is the correct syntax when declaring a pointer to a fixed size array. It is not something you usually see in C code but it is perfectly legal syntax. Back to my original question though. Why does gcc give that warning? It should be legal to point a const pointer to a non-const variable and use the pointer for read-only access, right? So why the warning? Is this a bug in GCC? Cheers --- On Mon, 11/30/09, me22 <me22.ca@xxxxxxxxx> wrote: > From: me22 <me22.ca@xxxxxxxxx> > Subject: Re: Warning when using const pointer to fixed size array > To: "Thomas Martitz" <thomas.martitz@xxxxxxxxxxxxxxxxxxxxx> > Cc: gcc-help@xxxxxxxxxxx > Received: Monday, November 30, 2009, 5:08 PM > 2009/11/30 Thomas Martitz <thomas.martitz@xxxxxxxxxxxxxxxxxxxxx>: > > > > I didn't try gcc, but visual studio compiler gives an > error on that one. > > > > I tried it in gcc 4.3.2, where it worked fine. > __________________________________________________________________ Looking for the perfect gift? Give the gift of Flickr! http://www.flickr.com/gift/