Am 01.12.2009 00:19, schrieb Aaron Rocha:
I am using :
$ gcc -dumpversion
4.2.4
$ gcc -dumpmachine
x86_64-linux-gnu
As expected, the following code does not generate any warnings when compiling with -Wall:
int main() {
int number = 0;
const int * const t =&number;
return *t;
}
However, this code does:
int main() {
int array[9] = {0};
const int (* const p)[9] =&array;
What address are you taking? "array" already stands for the address of
the first element (and is hence sort of a pointer). I'm not sure you can
take the address of the array name as I think it doesn't have one.
Maybe you want &array[0]?
