Matthias Kretz <Matthias.Kretz@xxxxxxxxxxxxxxxxxxxxx> writes: > I believe g++ is at fault here. You get a clearer error if you get rid of the template: struct B { float *f; }; struct A { A(const B *, const float *B::*) {} }; int main() { B x; A y(&x, &B::f); return 0; } g++-4.3.1 reports: constructor.cc: In function ‘int main()’: constructor.cc:14: error: invalid conversion from ‘float* B::*’ to ‘const float* B::*’ constructor.cc:14: error: initializing argument 2 of ‘A::A(const B*, const float* B::*)’ There is no implicit conversion from float* B::* to const float* B::*. There is however a conversion to const float* const B::*. So if you change the original template to struct A { template<typename T> A(const T *, const float *const T::*) {} }; then it will compile. If there were an implicit connversion from float* B::* to const float* B::*, you could inadvertently do: struct B { float *f; }; const float c = 0; int main() { B b; float* B::*p = &B::f; const float* B::*q = p; /* luckily not allowed */ b.*q = &c; /* modifies b.f */ *b.f = 1; /* tries to modify c, raises SIGSEGV */ } which perhaps is less likely than inadvertently dereferencing a pointer that points to freed memory, but still.