What would it turn this into, Andrew? if (!(foo || bar)) > Andrew Haley wrote: > > > gcc looks at > > > > if (!foo && !bar) > > ... > > > > and turns it into > > > > if (foo|bar) > > goto x; > > ... > > x: > > > > So, from Valgrind's point of view, the branch depends on the value of > > bar, which is uninitialized. We know that if foo is nonzero there is > > no such dependency, but Valgrind would have to do some heavyweight > > dependency analysis to figure that one out. > > Ding-ding-ding... and the winner is, I'm not awake enough yet this > morning :-) Thanks for the explanation! > > -- > Kevin P. Fleming > Digium, Inc. | Director of Software Technologies > 445 Jan Davis Drive NW - Huntsville, AL 35806 - USA > skype: kpfleming | jabber: kpfleming@xxxxxxxxxx > Check us out at www.digium.com & www.asterisk.org > > ________________________________________________________________ Please visit a saintly hero: http://www.jakemoore.org
