According to 6.3.2.1 Para 3, the type conversion from "array of type"
to "pointer to type" should
happen irrespective of whether the operand is on right had side or the
left hand side of assignment
operator. But GCC is converting only the right side operator type to
"pointer of type" while retaining the
left hand side type to be "array of type".
-Dharmendra
On Sat, Jul 18, 2009 at 3:51 PM, Andrew Haley<aph@xxxxxxxxxx> wrote:
> On 07/18/2009 10:35 AM, dharmendra pandit wrote:
>> Hi,
>>
>> I tried the following simple code segment in gcc and it gave the
>> incompatible type error as mentioned below.
>>
>> int main() {
>> int arr[10];
>> arr = arr; // error: incompatible types when assigning to type
>> ‘int[10]’ from type ‘int *’
>> }
>>
>> Here it seems GCC is retaining the left hand side type of arr to be
>> array of 10 ints whereas on the right hand side
>> it has changed its type from array to pointer to integer. I tried
>> searching the relevant sections in the standard ISO C
>> document number WG14/N1124 justifying the above behaviour of GCC but
>> failed to conclude it from the specifications.
>> It would be of great help if someone can point me out the relevant
>> sections from the specs.
>
> 6.3.2.1 Para 3.
>
> I'm surprised you ask, since this convention has been used since early
> K&R C.
>
> Andrew.
>
>
