Hi, As far as I have been able to find out it is not possible to write an interrupt function where its address is added to a selectable position in the vector table automatically by the compiler/linker. Just to be certain would that be right? Would I be correct in thinking that a normal function could be used as an ISR in which case I do not need to use the __attribute__((interrupt)) at all? If this is the case what is this attribute used for? Regards John -- View this message in context: http://www.nabble.com/Adding-the-address-of-an-exception-interrupt-handler-to-the-vector-table-tp23301224p23301224.html Sent from the gcc - Help mailing list archive at Nabble.com.
