using std::__enable_if template as constructor parameter

[Michal Bukovský <michal.bukovsky@xxxxxxxxxxxxxxx>]

Hello,

    I try use std::__enable_if as class constructor but gcc don't see
    this constructor while I try use it. Then I write small bit of code,
    which I think, is same and gcc don't compile this too.

    template <typename>
    struct is_allowed {};

    template <>
    struct is_allowed<int> { typedef int type; };

    class SomeObject {
    public:
        template <typename Type>
        SomeObject(const typename is_allowed<Type>::type &) {}
    };

    int main(int /*argc*/, char *[] /*argv*/) {
        SomeObject o(1);
    }

    Gcc says:

    a.cc: In function ‘int main(int, char**)’:
    a.cc:112: error: no matching function for call to ‘SomeObject::SomeObject(int)’
    a.cc:105: note: candidates are: SomeObject::SomeObject(const SomeObject&)

    I can't understand why gcc don't instantiate constructor template
    SomeObject::SomeObject<>?

    Can anybody explain me this?

--
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Michal Bukovský
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