Thank you for your help. I used sizeof(int *) and it worked.
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
int main()
{
int i, j;
int **table1=malloc(10000000*sizeof(int*));
int *table1_aux=(int *)malloc(10000000*100*sizeof(int));
for (i=0; i<10000000; i++) table1[i]=table1_aux+i*100;
for (i=0; i<10000000; i++) {
for (j=0; j<100; j++) {
table1[i][j]=0;
}
}
printf("table1 ok\n");
int **table2=malloc(10000000*sizeof(int*));
int *table2_aux=(int *)malloc(10000000*100*sizeof(int));
for (i=0; i<10000000; i++) table2[i]=table2_aux+i*100;
for (i=0; i<10000000; i++) {
for (j=0; j<100; j++) {
table2[i][j]=0;
}
}
printf("table2 ok\n");
return 0;
}
--- Begin Message ---
Alexey Salmin wrote:
>> ^ This is wrong. Should be
>>
>> int **table1=malloc(10000000*sizeof(int**));
>>
>> The same error occurs several times.
>>
>> You also need
>>
>> if (!table1 || !table1_aux)
>> perror ("");
>>
>
> LOL, you've got to be kidding us :)
> "table1" is pointer to an array of (int *). That's why it has type (int **).
Sorry, thinko: sizeof(int*). Not that it will make any difference, of course.
The change from sizeof(int) to sizeof(int *) is still needed.
Andrew.
--- End Message ---
