Hi Richard,
On Wednesday 08 October 2008, Richard Harvey Chapman wrote:
> I was able to get rid of the warning by simply removing the "else". I
> had to modify your program slightly to run it to completion.
thank you, but ...
> #include <stdio.h>
>
> #define BREAK_ON_ERROR(i) \
> if (1) \
> { \
> if (i < 0) \
> break; \
> } \
> else do \
> { \
> } while (0) \
>
>
> #define BREAK_ON_ERROR2(i) \
> if (1) \
> { \
> if (i < 0) \
> break; \
> } \
> do \
> { \
> } while (0) \
This changes the semantics: The BREAK_ON_ERROR() macro should be
handled as one compound statement. The following statement should
work as well:
if (bar)
BREAK_ON_ERROR(buzz);
else
BREAK_ON_ERROR(buzz1);
Kind regards,
Frank
--
## Dept. of Computer Science, Dresden University of Technology, Germany ##
## http://os.inf.tu-dresden.de/~fm3 ##
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