John Love-Jensen wrote:
char *s="",t;
Here you have allocated one byte of memory for s.
int i,j,l,c=0;
printf("\n Enter String to be Bit Stuffed : ");
scanf("%s",s);
Here you are scanning into s. The s buffer is only one byte long.
Depending on your compiler settings, the s buffer may be read-only (or maybe
not... my C is rusty, and perhaps I'm referring to a C++ -ism). You have
not taken any precautions to insure that the scanf does not overflow the
buffer (out of bounds error, which could result in a SEGV).
IIRC, the code:
char *s = "hello";
...has an implicit cast-from-const (the RHS has type 'const char *'),
and trying to write to it will raise a SEGV. Before gcc4 there was
-fwrite-strings, which would put string constants in writable memory,
but it's been deprecated for a LONG time and was removed in gcc4.
--
Matthew
"NT was a marketing name that stood for New Technology, but it was still
an amusing coincidence that WNT was VMS with each letter replaced by the
next one."
-- Jeremy Reimer
