Re: Problems with pointer-to-members

[Richard Harvey Chapman <hchapman-gcc-help@xxxxxxxx>]

David Sveningsson wrote:
> Guilherme Müller skrev:
>  > //Here comes the annoying error
> > void foo2::DoSomething()
> > {
> > ReadCallback callback = WhenComplete;
> > DoAnything(callback);
> > }
>
> I believe you must write &Foo2::WhenComplete.

I believe that there is also a missing cast to (ReadCallback) since 
WhenComplete above is of type (foo2::*) and not (foo::*) as ReadCallback 
is defined.

Is there a way around this? That is, is it possible to define a method 
pointer type that requires the method to be a member of the base class 
or any derived class without having to use a cast in assignment? 
Presumably, the type here, (foo::*) rather than (::*), requires the base 
class because it intends to manipulate member data?

Not to mention the other two errors in the code of 
foo2::foo::WhenComplete which should be foo2::WhenComplete along with an 
accompanying declaration in class foo2.

R.