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Am 06.02.2008 um 16:57 schrieb Eljay Love-Jensen:
Hi Lars,
Here bar is a variable:
char const* const bar = "bar";
I realize that bar is a const pointer to const char (array). But
the bar identifier itself is a fixed variable, and not a constant.
Here foo is a constant:
char const foo[] = "foo";
It's easy to conflate foo for a pointer, since, in C (and C++),
array constants degenerate into pointers quite promiscuously. Just
look at them funny, and they turn into pointers, as if you had
typed &foo[0].
Hence you can do this:
char const* const quux[] =
{
foo
};
But you cannot do this:
char const* const baz[] =
{
bar
};
C++ has slightly different rules, so it can do the later.
HTH,
--Eljay
Thanks a lot for this explanation, it is a bit more clear for me now!
Lars
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