Hi! I'd like to mark a class as deprecated, i.e. any instantiation or method call should be warned. After reading http://gcc.gnu.org/onlinedocs/gcc-4.1.2/gcc/Type-Attributes.html#Type-Attributes I concluded that class Foo { public: void bar(int x); } __attribute__ ((deprecated)); should do the trick. However int main() { Foo f; return 0; }; only warns about the (obviously) unused variable but nothing else: beachboys++ /tmp> make g++ -Wall foo.cc -o foo foo.cc: In function ?int main()?: foo.cc:11: warning: unused variable ?f? beachboys++ /tmp> g++ --version g++ (GCC) 4.1.2 20061115 (prerelease) (Debian 4.1.1-21) Copyright (C) 2006 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. Same effect with gcc 3.3 and 3.4. However a typedef Foo Quux __attribute__ ((deprecated)); with int main() { Quux f; return 0; }; does what I expected: foo.cc: In function `int main()': foo.cc:11: warning: `Quux' is deprecated (declared at foo.cc:8) foo.cc:11: warning: unused variable `Quux f' Did I understand anything wrong? Or is this a bug/feature? :-) Please CC me on reply, I'm not subscribed to gcc-help. Cheers Thimo
