kanishk rastogi writes:
> On 11/24/06, Andrew Haley <aph@xxxxxxxxxx> wrote:
> > kanishk rastogi writes:
> > > On 11/24/06, Andrew Haley <aph@xxxxxxxxxx> wrote:
> > > > kanishk rastogi writes:
> > > > > if i call a func like:
> > > > >
> > > > > func("kanishk");
> > > > > the string "kanishk" will be defined in readonly segment or in read -
> > > > > write segment ?
> > > > > if they will be in read-only segment i dont want that....
> > > > > how can this be done
> > > >
> > > > Dammit, how many times do I have to repeat this?
> > > >
> > > > You just gotta declare them right. Like this:
> > > >
> > > > char s[] = "kanishk";
> > > > func(s);
> >
> > > thanks for the advice andrew
> > > and sorry for the annoyance
> > > but the fact is I cant change the code because its more than 8000
> > > lines so i am asking for a feature in gcc which i would have missed
> >
> > Your code is wrong. "How do I get gcc to compile this code with these
> > bugs?" is not a sensible question. Fix the bugs!
> sorry
> the code is not buggy. i think u have misunderstood the real problem statement.
>
> so the problem in more detail is as below:
>
> printf("kanishk");
>
> the above code compiles perfectly with gcc -Wall.
> gcc by default puts the string into read execute segment,but i want to
> put string "kanishk" into writeable memory (or other than read execute
> segment). Is there a way for doing this without making any change in
> calling sequence (for example it may be regulated by some switch in
> gcc) or there is no provision in C99 standard for it.
OK, if it's not a bug, I need to ask another question. I don't
understand you at all: why do you want to put a constant string into
writable memory? Is this embedded, or what?
Andrew.
