RE: trying to understand: "warning: function declaration isn't a prototype"

["John Yates" <jyates@xxxxxxxxxxx>]

Ian Lance Taylor wrote:
>
> The warning means that the code does something like this:
>      extern int foo ();

To which Jay Vaughan replied:
>
> yes, i understand this - i do not want to ignore this warning, i want 
> to understand why the warning is emitted in the first place ..


I believe the issue is that empty parentheses do not constitute a valid
prototype and that to be truly conformant you would have to write:

    extern int foo (void);

/john