Re: Fwd: error in variable dereferencing

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Thibaud GUERIN writes:
 > On 4/21/06, Andrew Haley <aph@xxxxxxxxxxx> wrote:
 > > Thibaud GUERIN writes:
 > >  > On 4/20/06, Andrew Haley <aph@xxxxxxxxxx> wrote:
 > >  > > Thibaud GUERIN writes:
 > >  > >  >
 > >  > >  >
 > >  > >  > Not clear in the first message, (and maybe not in this one too..), sorry
 > >  > >  >
 > >  > >  >
 > >  > >  > This asm inline was something like a "test/patch code".
 > >  > >  >
 > >  > >  > I try to have a simple :
 > >  > >  >
 > >  > >  > char        **ap = (char **)(&fmt);
 > >  > >
 > >  > >  > so i try by my self... to do :
 > >  > >  >
 > >  > >  > ap = &fmt;
 > >  > >  > *ap = fmt;
 > >  > >  >
 > >  > >  > in asm inline.... (dirty i know...)
 > >  > >  >
 > >  > >  > problem is :
 > >  > >  > With this asm code in the binary *s is equal to fmt
 > >  > >  > Without this asm code in the binary *s isn't equal to fmt
 > >  > >  >
 > >  > >  >
 > >  > >  > All the 's' variable stuffs are from my debug...
 > >  > >  > Again :
 > >  > >  > My only aim is to have an 'ap = &fmt' valid (->ap = &fmt AND *ap = fmt)
 > >  > >
 > >  > > So why not do the obvious
 > >  > >
 > >  > >   const char **ap = &fmt ;
 > >  > >
 > >  > > ?
 > >  >
 > >  > because i need to do some :
 > >  > ap++;
 > >  > to get the next args in stack, as my end aim is to do re-write a printf...
 > >
 > > So why not use va_list?  That's what va_list is for.
 > >
 > >  > >  > The resulting asm was here to help you to understand wath's wrong ....
 > >  > >  > I'm looking for some days now without answer...
 > >  > >
 > >  > > You're still not explaining yourself.  You have a const char* arg that
 > >  > > you are trying to alter, but instead of doing it the obvious way with
 > >  > > an assignment, you're taking the address of the arg, casting the
 > >  > > resulting pointer to a different pointer type, and then overwriting
 > >  > > the arg through the resulting pointer.
 > >  > >
 > >  > > What's the point of all this?
 > >  >
 > >  > i'm not trying to alter an (const char*) but to get the args in my
 > >  > stack by getting some pointers on it, as in all va_args fonctions....
 > >
 > > Trying to do all this stuff behind the compiler's back is likely to
 > > break things.  Use va_list.
 > 
 > quote :
 > I'm compiling with (to run on my VM):
 > -std=gnu99 -Wall -Werror -nostdinc -Wstrict-aliasing=2 -fno-builtin 
 > -I../include -I../
 > 
 > no-builtin ....
 > 
 > I'm doing that because the va_list wasn't working too... (i come to
 > that dirty code by simplifing the code to found the root of the
 > problem)

OK, so now I know what you're _really_ trying to do.  It took some
work, but we're here now.

 > And my final aim is to have a printf without any deps form any parent
 > system (no use of standard includes, ....)

Fair enough.  va_list and its friends can't be written in C, which is
why gcc provides builtin functions for them.  The standard ones look
like this:

#define va_start(v,l) __builtin_va_start(v,l)
#define va_end(v) __builtin_va_end(v)
#define va_arg(v,l) __builtin_va_arg(v,l)
#define va_copy(d,s) __builtin_va_copy(d,s)

Now, if you know absolutely for sure that your args are pushed onto
the stack in order without any holes, you might be able to get around
this.

void pkludge (char *s, ...) __attribute__((noinline));
void pkludge (char *s, ...)
{
  void **p = &s;
  printf ("%d\n", *(int *)++p);
  printf ("%d\n", *(int *)++p);
}

This isn't legal C, though, and trying to do things like this behind
gcc's back is asking for trouble.  The _real_ solution is to find out
why gcc's builtins are not working.

Andrew.


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