Hi,
U missed the forward declaration for "friendclass".
I was using gcc 3.4.0 on a SUN box.
But i could not figure out why it was working without the namespace.
Any pointers?
On 12/30/05, Radhika Ganganna <Radhika.Ganganna@xxxxxxxxxx> wrote:
> Hi,
>
> I have a program that has a template base class with a private data member
> in it. It has a derived class. And both the base and derived class have a
> common friend class. All these classes are part of a namespace. When I try
> to access private data member of base class, through the derived class in
> friend class, I get the following compilation error:
>
> Linux:/user/rgangann >gcc rad.cpp
> rad.cpp: In member function `void radhika::friendclass::disp()':
> rad.cpp:4: error: `char**radhika::Base<char*>::num1' is private
> rad.cpp:17: error: within this context
>
> The code is as below:
>
> namespace radhika {
> template<class T> class Base { friend class friendclass;
> private: T* num1; };
>
> class Derived : protected Base <char * > {
> friend class friendclass;
> char ** num2;
> };
>
> class friendclass
> {
> void disp(void)
> {
> Derived d;
> char** a;
> a = d.num1;
> }
> } ;
>
> }; // End namespace radhika
>
> int main()
> {
> return 0;
> }
>
>
> I'm using gcc3.4.3. Let me know if this is an existing problem and how to
> solve this problem. Also I find that when I do not have the classes in
> namespace, the program works fine.
>
> Regards,
> Radhika
>
>
>
>
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