Hello Ladislav! On Tuesday 15 November 2005 21:33, Ladislav Mecir wrote: > >But why doesn't gcc warn about this code > > > > s.a = s.a++; > > p->a = p->a++; > > because in both these cases the result *is* defined I do not understand, why are those operations defined, but i = i++; is not? I fail to see the relevant difference in these assigments. Thanks for your help, Cheers Daniel
