On 9/29/05, John Love-Jensen wrote: > The f2 function returns an auto_ptr<const A>. > You are trying to return an auto_ptr<const B>. > An auto_ptr<const B> is not an auto_ptr<const A>, regardless if a "B is an > A". And it does not matter that there is an implicit conversion possible between auto_ptr<const B>& and auto_ptr<const A> ? (unless I explicitly state I want to do it, as in "f1" ) Regards, Dima.
