Re: "variable-size type declared" error for const sized array

[Bahadir Balban <krupiyer@xxxxxxxxx>]

>Hi Bahadir,
>
>It worked for me.
>
>Could you provide an example that illustrates the problem >you are
experiencing?
>
>Is it in C or C++ or some other language?
>
>What version of GCC you are using?
>
>What is your command line to compile your code?
>
>Thanks,
>--Eljay

Hi Eljay,

I see that it works when the array is a local variable. But in the
following piece of code:

#include <stdio.h>

// const int const_asize = 10;
#define  define_asize = 10;

int array[define_asize] = {1,2,3,4,5,6,7,8,9,0};

int main(int argc, char * argv[])
{

    return 0;
}


With a define it compiles with no errors, however if you replace it
with the constant variable, I get the following error:

"error: variable-size type declared outside of any function"
"error: variable-sized object may not be initialized"

This is on gcc version 3.3.5 compiling with the following:

gcc -o consttest main.c

adding a -std=gnu99 does not make any difference. 

My opinion is that it is not the best behaviour to differentiate
between a literal and a const int when they're declared global, but
make no distinction when they're local. What do you think?

Thanks,
Bahadir