Hi,
I hope this is at least the correct address to ask such questions.
I have the following small programm, and I don't understand why the
number is feeded with ones from the right, but not with zeros. And the
next question would be: How can I manage it to get zeros, instead of ones?
I'm still using gcc-3.4.4 but with a bunch of Gentoo patches. I tried
the 4.0.1 cvs, but it gave me several errors.
Thank you
void printint(unsigned long int toprint){
int i, var=toprint;
printf("printint: %d\n", var);
for(i=0; i<32; i++){
printf("%d_", var & 0x1);
var >>= 1;
}
printf("\n");
}
int main(){
int i, end, srt = 1;
//This gives us the number -2147483648, which has only the first
bit a one, and the rest zeros
for(i=0; i<31; i++){
srt <<= 1;
}
printf("the number reads: %d\n", srt);
end = 0;
for(i=0; i<32; i++){
printint(end);
end >>= 1;
if(i==3){//not necessary 3, but any number x: 0<x<32
printf("inif!!!!!!!!!!!!!!!!!!!!!!1\n");
end |= srt;//-2147483648
}
}
printf("FINAL: %d\n", end);
return 0;
}