Morten, Yes, you could even write the keyword 'typename' in the for statement. Did you read the 3rd C++ bullet at http://gcc.gnu.org/gcc-3.4/changes.html? Basically, it is saying that any type from a template parameter, must be explicitly marked as such with the 'typename' keyword. corey On Mon, 07 Feb 2005 19:54:58 +0100, Morten.Gulbrandsen <f1000mhz@xxxxxxxx> wrote: > corey taylor wrote: > > >Moten, > > > > I think this is *best* explained by the gcc release notes for 3.4 > > > > This release is the first one to throw this as an error and not a > >warning as you can produce in gcc 3.3. > > > > http://gcc.gnu.org/gcc-3.4/changes.html > > > > Under C++. The third bullet. > > > > The summary is that you need to explicitly specify that > >const_iterator with the 'typename' keyword before it. > > > >corey > > > > > > > > > Thanks, this should be correct ? > > // > // Display map properties > // > template<class T, class A> > void ShowMap(const map<T, A>& v) > { > > typename map<T, A>::const_iterator ci; > > for ( ci = v.begin(); ci != v.end(); ++ci) > cout << ci->first << ": " << ci->second << "\n"; > > cout << endl; > } > > instead of incorrect : > > template<class T, class A> > > void ShowMap(const map<T, A>& v) > > { > > for (map<T, A>::const_iterator ci = v.begin(); // line 107 > > > > /*=======================!!=========================*/ > > > > ci != v.end(); ++ci) > > cout << ci->first << ": " << ci->second << "\n"; > > > > cout << endl; > > } > > if this is correct then I have inderstood it, > > 'typename' was greek to me > > best regards > > Morten Gulbrandsen > >
