Ian Lance Taylor <ian@xxxxxxxx> writes:
> For example, given
> char *p;
> void foo() { p++; }
> Then it is correct for p to be incremented by 4 on a machine with
> 32-bit addresses and 8-bit bytes.
But, whoops, I got the example wrong. I should have said
int *p;
void foo() { p++; }
Then p might have the value, e.g., 0x100 before calling foo, and x0104
after.
Sorry for the confusion.
Ian
